- 200
- 250
- 200√2
- 200√3

Option 3 : 200√2

Free

SSC CHSL: Full Mock Test

229235

100 Questions
200 Marks
60 Mins

Suppose the height of the mobile tower is h.

∴ ED = h

In ΔBDE –

⇒ tan45° = ED/BD

⇒ 1 = h/BD

⇒ BD = h

Similarly, in ΔEDC –

⇒ tan45° = ED/DC

⇒ DC = h

In ΔAED-

∠EAD = 45°, ∠EDA = 90°, so, ∠DEA = 45°

∴ AD = DE = h

In ΔADB –

⇒ AB^{2} = AD^{2} + BD^{2}

⇒ 400^{2} = h^{2 }+ h^{2}

⇒ 2h^{2} = 400^{2}

⇒ h = 400/√2

⇒ h = 200√2 m

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